[C#] 两数之和解法

Example 1:

Input: nums = [2,7,11,15], target = 9
Output: [0,1]
Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
Example 2:

Input: nums = [3,2,4], target = 6
Output: [1,2]
Example 3:

Input: nums = [3,3], target = 6
Output: [0,1]

下方为 Example 1 解法

       static void Main(string[] args)       {           TwoSum();       }       private static void TwoSum()       {           var nums = new int[] { 2, 7, 11,15};           int target = 9;           var result = TwoSum(nums, target);           Console.WriteLine($"目标索引:{result[0]},{result[1]}");           Console.ReadKey();       }       /// <summary>       /// 两数之和       /// </summary>       /// <param name="nums">数组</param>       /// <param name="target">目标值</param>       /// <returns></returns>       private static int[] TwoSum(int[] nums, int target)       {           int left = 0;           int right = nums.Length - 1;           while(left < right)           {               int sum = nums[left] + nums[right];               if(sum == target)               {                   return [left, right];               }               else if(sum < target)               {                   left++;               }               else if (sum > target)               {                   right--;               }           }           return [ -1, -1 ];       }